Thermodynamics is a vital part of NEET Chemistry, bridging physical science concepts with chemical behavior. It helps explain how and why chemical reactions occur—whether they release or absorb energy, and whether they are spontaneous or require external input. Despite seeming theory-heavy, Thermodynamics is actually a conceptual and scoring chapter for NEET aspirants.

This chapter typically contributes 2–3 questions every year in the NEET exam. The beauty of Thermodynamics lies in its formula-driven nature. Questions are rarely calculation-intensive; instead, they test understanding of relationships between heat, work, energy, enthalpy, entropy, and spontaneity.

Rather than memorizing everything, students can score well by understanding the core formulas, knowing sign conventions, and interpreting conditions for spontaneity using Gibbs Free Energy. Most questions are NCERT-based and revolve around direct formula applications or conceptual clarity. This makes Thermodynamics a high-return chapter—especially for those aiming to boost their marks in Physical Chemistry.

With the right strategy—focusing on definitions, laws, energy changes, and formula applications—this chapter becomes easy to revise and rewarding to master.

Thermodynamics in NEET: Weightage & Trends

NEET Previous Year Question Paper

Over the past five NEET exams, Thermodynamics has consistently contributed 2 to 3 questions, often spread across Physical Chemistry and its applications.

YearNo. of QuestionsType
NEET 20202Conceptual + ΔG/ΔH relation
NEET 20213Gibbs Free Energy, Entropy
NEET 20222Formula-based
NEET 20233Enthalpy + Thermochemical
NEET 20242Concept recall + Calculation

NEET favors conceptual clarity in Thermodynamics rather than complex numericals. For example, you’re more likely to see a question asking whether a reaction is spontaneous based on ΔH and ΔS, rather than one that requires a lengthy derivation.

Also, Thermodynamics often overlaps with chapters like:

  • Chemical Thermodynamics (heat, work, enthalpy, internal energy)
  • Thermochemistry (heat of reactions, Hess’s law)
  • Equilibrium and Kinetics, when connected with energy profiles

This interlinking means that mastering Thermodynamics supports understanding in other areas too, especially when dealing with energy-based reasoning or temperature effects on reactions.

Laws of Thermodynamics Simplified

First Law of Thermodynamics

The First Law is based on the principle of conservation of energy. It states that energy can neither be created nor destroyed, only converted from one form to another.

Formula:
boldsymbol{Delta U = q + w}
Where:

  • boldsymbol{Delta U} = Change in internal energy
  • boldsymbol{q} = Heat added to the system
  • boldsymbol{w} = Work done on the system

Sign convention:

  • Heat added to the system → boldsymbol{q} is positive (+ve)
  • Work done on the system → boldsymbol{w} is positive (+ve)

This law explains how heat and work affect the internal energy of a system—critical to understanding energy flow during chemical reactions.

Second Law of Thermodynamics

This law deals with spontaneity and the concept of entropy (S), which is the measure of disorder or randomness in a system.

Key idea: A spontaneous process increases the total entropy of the universe.

Two important statements:

  • Kelvin-Planck Statement: No engine can convert all heat into work; some energy is always lost.
  • Clausius Statement: Heat cannot spontaneously flow from a colder body to a hotter one.

Together, these statements help explain why reactions happen and why some are irreversible.

Third Law of Thermodynamics

This law states:
“The entropy of a perfect crystal at absolute zero (0 K) is zero.”

At 0 K, there is no movement, hence no disorder, so S = 0.

While not often tested directly in NEET, this law lays the groundwork for calculating absolute entropies and understanding thermodynamic stability at low temperatures.

Important Thermodynamic Terms

Internal Energy (U)

Internal Energy is the total energy contained within a system, including the kinetic and potential energy of its molecules. It is denoted by U and is a state function, meaning it depends only on the current state of the system, not how it got there.

In thermodynamics, the change in internal energy (ΔU) tells us how the energy of a system has changed due to heat (q) and work (w):

boldsymbol{Delta U = q + w}

This relationship is at the heart of the First Law of Thermodynamics. In NEET, questions often test your understanding of how internal energy is affected by heat flow and work done.

Mock Tests for NEET 2025

Enthalpy (H)

Enthalpy (H) represents the heat content of a system at constant pressure. It’s especially useful for describing heat changes in chemical reactions.

boldsymbol{Delta H = H_{text{final}} - H_{text{initial}}}

  • boldsymbol{Delta H < 0} → Exothermic reaction (heat is released)
  • boldsymbol{Delta H > 0} → Endothermic reaction (heat is absorbed)

Enthalpy is also used to calculate heat changes using Hess’s Law, a concept frequently tested in NEET. Understanding whether a reaction is exo or endothermic helps determine spontaneity when combined with entropy and temperature.

Entropy (S)

Entropy (S) is a measure of disorder or randomness in a system. The greater the disorder, the higher the entropy.

  • Solids have low entropy, gases have high entropy.
  • During spontaneous processes, the total entropy of the universe increases.

NEET commonly tests this concept through reaction conditions (solid → gas, temperature changes, etc.) and the role of entropy in determining Gibbs Free Energy.

Gibbs Free Energy & Spontaneity

Gibbs Free Energy (G) helps predict whether a reaction will occur spontaneously under constant temperature and pressure.

Gibbs Equation:

boldsymbol{Delta G = Delta H - TDelta S}

Where:

  • boldsymbol{Delta G} = Gibbs free energy change
  • boldsymbol{Delta H} = Enthalpy change
  • boldsymbol{T} = Temperature in Kelvin
  • boldsymbol{Delta S} = Entropy change

Spontaneity Conditions:

  • boldsymbol{Delta G < 0} → Reaction is spontaneous
  • boldsymbol{Delta G = 0} → Reaction is in equilibrium
  • boldsymbol{Delta G > 0} → Reaction is non-spontaneous

This equation links energy, entropy, and temperature, making it a core concept in Thermodynamics MCQs.

boldsymbol{Delta G} and Equilibrium Constant
The relationship between boldsymbol{Delta G^circ} and the equilibrium constant (boldsymbol{K}) is:
boldsymbol{Delta G^circ = -RT ln K}

Interpretation:

  • If boldsymbol{K > 1}boldsymbol{Delta G^circ} is negative → spontaneous
  • If boldsymbol{K < 1}boldsymbol{Delta G^circ} is positive → non-spontaneous
  • If boldsymbol{K = 1}boldsymbol{Delta G^circ = 0} → equilibrium

This is frequently asked in NEET as part of application-based questions involving spontaneity or equilibrium direction.

Quick Revision Table: Key Thermodynamics Formulas

FormulaMeaning / Application
boldsymbol{Delta U = q + w}First law of thermodynamics – change in internal energy
boldsymbol{q = m times c times Delta T}Heat energy change (mass × specific heat × temperature change)
boldsymbol{Delta G = Delta H - TDelta S}Gibbs Free Energy – predicts spontaneity
boldsymbol{Delta G^circ = -RT ln K}Free energy and equilibrium constant relationship
boldsymbol{Delta H = sum Delta H_{text{products}} - sum Delta H_{text{reactants}}}Enthalpy change for a reaction using Hess’s Law

Tips to Remember:

  • Use Kelvin for temperature in all thermodynamic formulas.
  • For spontaneity, remember “NEGATIVE ΔG = GO reaction”.
  • Use ln K (natural log) when calculating ΔG° with the equilibrium constant.

…(existing content remains unchanged)

Previous Year NEET Questions (PYQs)

NEET 2024

Q1. For the reaction:
boldsymbol{text{C(graphite) + O}_2text{(g)} rightarrow text{CO}_2text{(g)}}
boldsymbol{Delta H = -393.5 text{ kJ/mol}} and boldsymbol{Delta S = -2.5 text{ J/mol·K}}.
Predict the spontaneity of the reaction at 298 K.
Answer: Spontaneous
Explanation:
boldsymbol{Delta G = Delta H - TDelta S}
boldsymbol{Delta G = -393.5 times 1000 - (298 times -2.5)}
Delta G is large negative → Reaction is spontaneous.
This tests the application of Gibbs Free Energy formula.

NEET 2023

Q2. Which of the following processes results in an increase in entropy?
A) Condensation of steam
B) Freezing of water
C) Sublimation of iodine
D) Formation of NaCl from Na and Cl₂
Answer: C
Explanation: Sublimation = solid to gas → increase in disorder (entropy).

NEET 2022

Q3. The work done in expansion of an ideal gas is maximum under which condition?
A) Adiabatic
B) Isochoric
C) Free expansion
D) Isothermal reversible
Answer: D
Explanation: Isothermal reversible expansion yields maximum work.

NEET 2021

Q4. The standard enthalpy of formation of an element in its standard state is:
A) Positive
B) Negative
C) Zero
D) Depends on temperature
Answer: C
Explanation: By definition, standard enthalpy of formation of elements in standard state = 0.

Practice Questions for Students

Concept-Based MCQs

Q1. Which of the following is true for a spontaneous process?
A) boldsymbol{Delta G > 0}
B) boldsymbol{Delta G = 0}
C) boldsymbol{Delta G < 0}
D) boldsymbol{Delta H > 0}

Q2. Entropy change is positive when:
A) Water freezes
B) Ice melts
C) Steam condenses
D) Gas turns to liquid

Q3. First Law of Thermodynamics is based on:
A) Entropy conservation
B) Energy conservation
C) Spontaneity
D) Free energy change

Numerical-Based MCQs

Q4. Calculate Delta G at 300 K if Delta H = -100 text{ kJ/mol} and Delta S = -0.2 text{ kJ/mol·K}.
(Use Delta G = Delta H - TDelta S)

Q5. If Delta G^circ = -5.7 text{ kJ/mol} at 298 K, find the value of K using:
Delta G^circ = -RT ln K
(R = 8.314 J/mol·K)

Answers

A1. C
Explanation: Spontaneous process → Delta G < 0

A2. B
Explanation: Melting increases disorder (entropy)

A3. B
Explanation: First law = Conservation of energy

A4.
Delta G = -100 - (300 times -0.2) = -100 + 60 = -40 text{ kJ/mol}

A5.
Delta G^circ = -RT ln K
Rightarrow ln K = frac{-(-5700)}{8.314 times 298} = 2.3
Rightarrow K = e^{2.3} approx 10

Common NEET Mistakes in Thermodynamics

Sign Confusion in Work/Heat

In NEET, students often mix up when to use +ve or -ve signs.

  • Heat absorbed → q is positive
  • Work done by the system → w is negative
    Stick to the standard NEET/NCERT sign convention:
    boldsymbol{Delta U = q + w} (with work done on the system taken as positive)

Misunderstanding Delta G Values

Many aspirants confuse:

  • boldsymbol{Delta G < 0} → Spontaneous
  • boldsymbol{Delta G = 0} → Equilibrium
  • boldsymbol{Delta G > 0} → Non-spontaneous

Use the memory aid:
Negative Delta G? Good to Go!” → Reaction proceeds spontaneously.

Forgetting Temperature in Kelvin

Temperature must always be in Kelvin when using formulas like:
boldsymbol{Delta G = Delta H - TDelta S} or boldsymbol{Delta G^circ = -RT ln K}

Remember:
boldsymbol{T(^circ C) + 273 = T(K)}
A small mistake here can lead to completely incorrect answers in numerical problems.

FAQs on Thermodynamics for NEET

Is Thermodynamics a difficult chapter in NEET?

No, Thermodynamics is not difficult if approached the right way. NEET doesn’t test complex derivations or lengthy numerical problems. Instead, it focuses on conceptual clarity, basic formula application, and factual recall. Most questions are based directly on NCERT concepts like Gibbs Free Energy, entropy changes, and enthalpy values, making this a moderately easy and scoring chapter with consistent weightage in the exam.

Are derivations important?

Not really. NEET does not ask for detailed derivations. However, understanding the logic behind key formulas—like ΔG = ΔH – TΔS or ΔG° = –RT ln K—helps in applying them correctly. Students should focus more on formula application, sign conventions, and interpretation rather than deriving equations from scratch.

How to quickly revise thermodynamics formulas?

Here’s how you can revise Thermodynamics efficiently:

  • Create a formula flashcard or summary sheet with ΔG, ΔH, ΔS, ΔU equations.
  • Memorize units and temperature conversion (always in Kelvin).
  • Solve at least 10 previous year questions based on formulas.
  • Use memory aids like:
    • “Negative ΔG = Spontaneous”
    • “Work done by system = Negative”

Daily practice with short quizzes or mock tests can help solidify retention before the exam.

Conclusion

Thermodynamics is a core Physical Chemistry chapter with high scoring potential in NEET. With just a few well-understood formulas and conceptual clarity, students can easily tackle the 2–3 questions that appear every year.

This chapter does not require deep mathematical ability but demands a clear grasp of energy changes, entropy behavior, and reaction spontaneity. Most questions are derived directly from NCERT, which makes it a smart topic to master during revision.

By focusing on:

  • Understanding key thermodynamic terms
  • Memorizing and applying core formulas
  • Practicing previous year questions

…you can convert this chapter into a high-return area for your NEET score. Combine your conceptual understanding with regular mock practice, and you’ll be well-prepared to handle Thermodynamics with confidence on exam day.